Trigonometry means (triangle
+ measure)
Trigonometry is all about triangle measurement.
Base of trigonometry is depending on Pythagorean theorem.
Pythagorean theorem is also known as Pythagoras theorem.
Pythagoras theorem –“In a right angle triangle the square of
a long side is equal to sum of the square of the other two sides.”
Let we assume that adjacent=x, opposite=y and hypotenuse=z.
We right this theorem like as Z2=X2 + Y2
With the help of this formula people can calculate
hypotenuse, adjacent and opposite easily if one is missing.
Now we measure the Angle(θ)
Suppose in a right angle triangle, we assume an angle θ,
then sine, cosine and tangent (special functions) help us.
Sine function; Sinθ
=opposite/hypotenuse.
Cosine function; Cosθ
=adjacent/hypotenuse.
Tangent function; Tanθ
=opposite/adjacent.
Some time we are very confused to these formulas.so we learn
these formulas in a simple way.
That is O A O/H H A,
so we learn like as –
Sinθ =O/H
=opposite/hypotenuse.sss
Cosθ =A/H
=adjacent/hypotenuse.
Tanθ =O/A
=opposite/adjacent.
Similar to sine, cosine and tangent functions, there are
three other trigonometry functions.
Cosecant function, secant function and cotangent function.
Cosecant function; cosecθ
=hypotenuse/opposite =H/O.
Secant function; secθ
=hypotenuse/adjacent =H/A.
Cotangent function;
cotθ =adjacent/opposite =A/O.
Some examples depend on these formulas.
1)in a right angle triangle adjacent (x)=5c.m and hypotenuse
(z)=13c.mthen find opposite with the help of Pythagoras theorem?
Solution-Pythagoras theorem is-
Z2 =X2 +Y2
Put the values in this formula-
(13)2 = (5)2 +Y2
169 = 25 + Y2
169 – 25 = Y2
144 = Y2
√144 = Y
Y = 12 c.m
Which is your answer.
2)In a right angle triangle x =6 meter and y = 8 meter then
find z with the help of Pythagoras theorem?
Solution- z2 =x2+ y2
Put the values-
Z2 = (6)2 + (8)2
Z2 = 36 + 64
Z2 =100
Z = √100
Z = 10 meter
Which is your answer.
3) In a right angle triangle adjacent =12, opposite =9 and
hypotenuse =15, then find the sine, tangent and secant functions.
Solution –
a)
Sinθ =opposite/hypotenuse = O/H
Sinθ = 9/15 (put the values)
Sinθ = 0.6
Which is your answer.
b) Tanθ = O/A
Tanθ = 9/12 (put the values)
Tanθ = 0.75
Which is your answer.
c)
Sacθ = H/A
Secθ =15/12 (put the values)
Secθ = 1.25
Which is your answer.
These are basics knowledge about
trigonometry. Trigonometry is full of formulas but if we don’t know about the
basics formulas, then we cannot solve any question in trigonometry.
The examples provided also demonstrate how these formulas can be used to solve real-world problems effectively. For students struggling with trigonometry, this is an excellent starting point to build confidence in the subject. If you need further support in mastering trigonometry, H2 Math Tuition offers personalized guidance to help you understand and apply these concepts with ease.
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