Thursday, 6 October 2016

INTRODUCTION - TRIGONOMETRY

Trigonometry means (triangle + measure)
Trigonometry is all about triangle measurement.
Base of trigonometry is depending on Pythagorean theorem. Pythagorean theorem is also known as Pythagoras theorem.
Pythagoras theorem –“In a right angle triangle the square of a long side is equal to sum of the square of the other two sides.”
Let we assume that adjacent=x, opposite=y and hypotenuse=z.
We right this theorem like as Z2=X2 + Y2


With the help of this formula people can calculate hypotenuse, adjacent and opposite easily if one is missing.
Now we measure the Angle(θ)
Suppose in a right angle triangle, we assume an angle θ, then sine, cosine and tangent (special functions) help us.

Sine function; Sinθ =opposite/hypotenuse
Cosine function; Cosθ =adjacent/hypotenuse.
Tangent function; Tanθ =opposite/adjacent.
Some time we are very confused to these formulas.so we learn these formulas in a simple way.
That is O A O/H H A, so we learn like as –
Sinθ =O/H =opposite/hypotenuse.sss
Cosθ =A/H =adjacent/hypotenuse.
Tanθ =O/A =opposite/adjacent.
Similar to sine, cosine and tangent functions, there are three other trigonometry functions.
Cosecant function, secant function and cotangent function.
Cosecant function; cosecθ =hypotenuse/opposite =H/O.
Secant function; secθ =hypotenuse/adjacent =H/A.
Cotangent function; cotθ =adjacent/opposite =A/O.
Some examples depend on these formulas.
1)in a right angle triangle adjacent (x)=5c.m and hypotenuse (z)=13c.mthen find opposite with the help of Pythagoras theorem?
Solution-Pythagoras theorem is-
Z2 =X2 +Y2
Put the values in this formula-
(13)2 = (5)2 +Y2
169 = 25 + Y2
169 – 25 = Y2
144 = Y2
√144 = Y
Y = 12 c.m
Which is your answer.
2)In a right angle triangle x =6 meter and y = 8 meter then find z with the help of Pythagoras theorem?
Solution- z2 =x2+ y2
Put the values-
Z2 = (6)2 + (8)2
Z2 = 36 + 64
Z2 =100
Z = √100
Z = 10 meter
Which is your answer.
3) In a right angle triangle adjacent =12, opposite =9 and hypotenuse =15, then find the sine, tangent and secant functions.
Solution –
a)      Sinθ =opposite/hypotenuse = O/H
Sinθ = 9/15 (put the values)
Sinθ = 0.6
Which is your answer.
b) Tanθ = O/A
Tanθ = 9/12 (put the values)
Tanθ = 0.75
Which is your answer.
c)       Sacθ = H/A
Secθ =15/12 (put the values)
Secθ = 1.25
Which is your answer.

These are basics knowledge about trigonometry. Trigonometry is full of formulas but if we don’t know about the basics formulas, then we cannot solve any question in trigonometry.

Monday, 3 October 2016

Multiplication techniques with the help of Vedic mathematical

Learning to perform fast Vedic mathematical calculations will help you immensely irrespective of which field of life you deal with. Knowing the Vedic mathematical techniques will give you a positive edge over the others. If you are a student and you face exams or interviews for a job then you can use these techniques and tricks for a good result, and if you are engineer or teacher, you must use these techniques. learning this quick Vedic mathematical tricks and techniques is always going to benefit you.

For example,

let say you want to multiply 34*11. This can be calculated in less than 1 second with the help of Vedic mathematical techniques. if you want to do it traditionally, it will take you around 10 seconds. Isn’t it?



So let see how using Vedic mathematical techniques, this calculation can be done in a just 1-2 seconds...


To multiply 34 and 11,

First you take the sum of digits from the numbers other than 11.

That is 34. then

3+4=7

Now insert this 7 between 3 and 4 like as 374.

That is your answer.

34*11=374

 some more examples:


1) 62 * 11 = 6 (6+2) 2 = 682

2) 81 * 11 = 8 (8+1) 1 = 891
                                                                                                                                                                                                                                           
3) 72 * 11 = 7 (7+2) 2 = 792 etc...

With just a little bit of practice you can easily use this Vedic mathematical techniques in the blink of an eye.

Now a day’s people wants everything very fast from any way. If you are a teacher, then you think your student should complete their exams and take a good position. for this you teach all tricks and techniques to your student. From these Vedic mathematical techniques anyone calculate any calculation in just 1-2 second and give a good performance.

It will give you smartness and sharpness and an impressive personality also.

So these techniques play a very important role in every person who wants a good future.

NOTE:
This rule only applies on 2 digits’ numbers whose digit’s sum is less than or equal to 9.

Suppose it perfectly work on 54 because the sum of 5+4=9, so the answer is 54*11=594.


But it will not work on 55 because the sum of 5+5=10 and if we put 10 between 55 then the answer will be incorrect.

Thursday, 29 September 2016

Calculate the square of any number whose last digit is 5 with the help of Vedic math

Vedic mathematical techniques to calculate the square of any number whose last digit is 5.

Now a day’s people face many competition exam and mostly do not complete their exam because of

calculation. If people use Vedic mathematical techniques

They calculate any calculation very easily.

We take 20 or more seconds to calculate the square of any number. If we use these techniques, then we

calculate the square of any number in just 5 to 10 seconds.

Anyone can solve the complex mathematical calculation very easily with the help of Vedic mathematical

techniques.

Now we are going to learn how to calculate the square of any number whose last digit is 5.

For example:

1) Calculate the square of 35.

Now we use Vedic mathematical techniques:

First we square the 5 is 25. Then

Rest digit (rest digit + 1)

3 (3 + 1) =3*4

12

Now joint these calculations like as 1225.

So the square of 35 is 1225.

Similarly:



2) Calculate the square of 125.

(125) 2 = 12 (12 + 1) (5) 2

= (12* 13 )25

=15625 (which is the answer)

3) Calculate the square of 1625.

(1625) 2 =162 (162 + 1) (5 ) 2

= (162 * 163 )25

=2640625 (which is the answer)

Now a day’s people depends on calculators and mobiles. But when people sitting for

competitive exams often complain they could not complete the question paper

Within a certain time period as the paper was too lengthy.

If people use Vedic mathematical techniques, then they complete their question paper very

easily and quickly.

It will give you sharpness and smartness.